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A dietician wanted to test three different diets to find out if the mean weight loss for each of

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A dietician wanted to test three different diets to find out if the mean weight loss for each of these diets is the same.  She randomly selected 21 overweight persons, randomly divided them into three groups, Diet I, Diet II, and Diet III. After running an Anova, Single Factor hypothesis test on the data, she determined at least 2 means are different. 

In order to determine where the differences exist in an ANOVA test, Tukey developed another critical value and a procedure to find those differences.  When utilizing Tukey's Omega, given the following Excel print-out, can you determine the treatments in where the differences exist.

Multiple Comparisons
			LSD	Omega
Treatment	Treatment	Difference	Alpha = 0.05	Alpha = 0.05
Diet I	Diet II	-6.14286	4.73283	5.7505
	Diet III	-1	4.73283	5.7505
Diet II	Diet III	5.14286	4.73283	5.7505

 

a.	Difference is between ?Diet I? and ?Diet III
b.	According to Tukey?s Omega, there are no differences shown in the printout.
c.	Difference is between ?Diet I? and ?Diet II
d.	Difference is between ?Diet II? and ?Diet III

The null and alternative hypotheses are

 

( all the means are same)

 

H1: Not all three populations means are equal (at least one mean is different from others).

 

To Show the rejection and non-rejection...

 

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Oct 14, 2020

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